-7+11h=-6h^2

Solution for -7+11h=-6h^2 equation:

-7+11h=-6h^2

We move all terms to the left:

-7+11h-(-6h^2)=0

We get rid of parentheses

6h^2+11h-7=0

a = 6; b = 11; c = -7;
Δ = b2-4ac
Δ = 112-4·6·(-7)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-17}{2*6}=\frac{-28}{12}
=-2+1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+17}{2*6}=\frac{6}{12}
=1/2
$